sanju and manju went to a bakery shop. sanju ate 4 puffs, 3 burgers, 2 cakes, and used up all the money she had. manju ate 3 puffs,6 burgers,and 4 cakes and paid 25% more than that sanju paid . what % of sanju's money was spent on the puffs she ate? give me method and solve it please.......Sanju and manju went to a bakery shop.?
S - money Sanju spent
M - money Manju spent
p, b, c - prices of puffs, burgers and cakes, respective.
three equations
S = 4p + 3b + 2c ...(1)
M = 3p + 6b + 4c ... (2)
M = 1.25 S ... (3)
First, we'll eliminate M equalizing right sides of (2) and (3)
1.25 S = 3p + 6b + 4c ...(4)
when we compare this to (1) we can notice members containing b and c are scaled by factor two; we're gonna use this to eliminate both b and c.
Divide (4) by 2 to get
0.625 S = 1.5 p + 3b + 2c
move 1.5p to the left side so that group (3b+2c) stays alone on the right
0.625 S - 1.5 p = 3b + 2c ...(5)
Do the same with (1) to get:
S - 4p = 3b + 2c ...(6)
From (5) and (6)
0.625 S - 1.5 p = S - 4p
0.375 S = 2.5 p
p = 0.375 S / 2.5 = 0.15 S
This means price of one puff is 15% of money Sanju spent.
She bought 4 puffs so money she spent on puffs is 4*15=60% of all the money she had.
The answer is 60%
Note:
Instead of dividing (4) by 2, we could multiply (1) by 2 to get
2S = 8p + 6b + 4c
and then from this equation and (4):
2 S - 8p = 1.25 S - 3p
0.75 S = 5 p
price of one puff is
p = 0.75 S / 5 = 0.15 S
and price of 4 puffs is 0.6 S
- the same result as before.Sanju and manju went to a bakery shop.?
Let S be the money Sanju spent
M be the money Manju spent
p, b, c be the prices of puffs, burgers and cakes, respectively.
three equations that an be formed
S = 4p + 3b + 2c .....................(A)
M = 3p + 6b + 4c ... .................(B)
M = 1.25 S ............................ (C)
Multiply (A) by 2
2 S = 8p + 6b + 4c...................(D)
Deduct (B) from (D)
2S - M = 8p - 3p
2S - 1.25S = 5p
0.75S = 5p
0.15 S = p
But Sanju ate 4 puffs
4p = 0.15S x 4 = 0.6 S = 60% of S
So Sanju has spent 60 % of his money for the puffs
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